Question

Find the equation of a line that passes through the point (3,-1) and has a

gradient of 1/3
Leave your answer in the form y=mx + c

Answer 1

Answer: y=-4x/9 + 1/3

Explanation:

y=mx + c

**Substitute known variables into the equation**

-1=3m + 1/3

(-1=3m + 1/3)*3 ==> Multiply equation by 3 to get rid of fractions

-3=9m+1

9m=-4

m=-4/9

y=-4x/9 + 1/3