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The difference two positive integer is 3. If the smaller is added to the square of the larger the sun is 417 find the integers

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Answer:


17 and
20.

Explanation:

Let
x denote the larger one of the two positive integers (
x > 0.) The smaller integer would be
(x - 3). The square of the larger integer would be
x^(2).

The sum of the smaller integer and the square of the larger integer is
(x^(2) + (x - 3)). If this sum is equal to
417, then:


x^(2) + x - 3 = 417.


x^(2) + x - 420 = 0.

Solve this quadratic equation for
x through factorization. Since
420 = 21 * 20:


x^(2) + x - (21 * 20) = 0.


x^(2) + 21\, x - 20\, x + (21)\, (-20) = 0.


(x + 21)\, (x - 20) = 0.

Thus, either
x = 20 or
x = (-21) by the Factor Theorem. However, since
x > 0 (the two integers are both positive,) only
x = 20 is a valid solution.

Hence, the larger one of the two integers would be
20. The smaller one of the two integers would be
(x - 3) = (20 - 3) = 17.

User Kyshia
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