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Find the derivative of: 3x^5+5x^9

User Mirko Lugano
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1 Answer

5 votes
5 votes

Answer:


\frac{\text{d}y}{\text{d}x} =15x^4+45x^8

Explanation:


\boxed{\begin{minipage}{4.8 cm}\underline{Differentiating $ax^n$}\\\\If $y=ax^n$, then $\frac{\text{d}y}{\text{d}x}=nax^(n-1)$\\\end{minipage}}


\textsf{Differentiate $y$ with respect to $x$}:


\begin{aligned}y & = 3x^5+5x^9\\\\\implies \frac{\text{d}y}{\text{d}x} & = 5 \cdot 3x^(5-1)+9 \cdot 5x^(9-1)\\\\& = 15x^4+45x^8\end{aligned}


\textsf{Therefore, the derivative of $y$ with respect to $x$ is: $\frac{\textrm{d}y}{\textrm{d}x} =15x^4+45x^8$}

User Dave Paola
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3.5k points