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An unbiased coin is tossed 14 times. in how many ways can the coin land tails either exactly 8 times or exactly 2 times?

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Final answer:

The number of ways an unbiased coin can land tails exactly 8 times or exactly 2 times when tossed 14 times is found by summing the binomial coefficients (14 choose 8) and (14 choose 2).

Step-by-step explanation:

The question asks about the number of ways an unbiased coin can land tails exactly 8 times or exactly 2 times when tossed 14 times. This is a typical problem of binomial distribution, which falls under the subject of probability in mathematics.

To calculate the number of ways to get exactly 8 tails, we use the binomial coefficient (14 choose 8), which is calculated as 14!/(8!(14-8)!). Similarly, to calculate the number of ways to get exactly 2 tails, we use the binomial coefficient (14 choose 2), which is calculated as 14!/(2!(14-2)!).

The total number of ways the coin can land tails either exactly 8 times or exactly 2 times is the sum of these two binomial coefficients. Therefore, the answer is calculated by adding the result of (14 choose 8) and (14 choose 2).

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