Question

An engineering school reports that 56% of its students were male (M), 32% of its students were between the ages of 18 and 20 (A), and that 26% were both male and between the ages of 18 and 20.

What is the probability of choosing a random student who is a female or between the ages of 18 and 20? Assume P(F) = P(not M).

Your answer should be given to two decimal places.

Answer 1

.7

Explanation:

M= .56

A= .32

M∩A= .26

M'∪A= ?

M'∪A= M'+A-M'∩A

A=M∩A+M'∩A (law of total probability)

.32=.26+M'∩A

M'∩A= .06

M'∪A= (1-.56)+.32-.06= .7