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32 votes
32 votes
Find an equation of the line that is perpendicular to 10 x + 11 y = 10 and passes through ( − 4 , 8 )

User Viktor Luft
by
2.6k points

1 Answer

10 votes
10 votes

Answer:

y = (11/10)x + 62/5

Explanation:

First find the slope of the given line 10 x + 11 y = 10. To do this, solve this equation for y and take the slope of the line from the result:

11y = 10 - 10x, or y = (-10/11)x + C, where C is just a constant. The slope of the given line is (-10/11).

The slope of any line perpendicular to the one above has a slope which is the negative reciprocal of the slope of the given line:

The negative reciprocal of (-10/11) is (11/10).

Starting with the slope-intercept form y = mx + b, and substituting the knowns, we are able to find the value of b:

y = mx + b => 8 = (11/10)(-4) + b, or

8 = -44/10 + b, or

80 = -44 + 10b

Then 10 b = 124, and so b = 62/5

The desired equation is thus y = (11/10)x + 62/5

User Avishekh Bharati
by
3.3k points
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