Register
Find the HCF of: 6(p² +p-2), 15(p³ + 8) and 18(4p²-p-18)​
140k views
2 votes
Find the HCF of: 6(p² +p-2), 15(p³ + 8) and 18(4p²-p-18)​

User Peter Quan
by
5.5k points

1 Answer

7 votes

Answer:

Hello,


answer=\boxed{HCF=3*(p+2)}

Explanation:


6(p^2+p-2)=6(p+2)(p-1)\\\\15(p^3+8)=15(p+2)(p^2-2p+4)\\\\18(4p^2-p-18)=18(p+2)(4p-9)\\\\\boxed{HCF=3*(p+2)}

User Jianru Shi
by
5.5k points
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

5.9m questions

7.7m answers

Other Questions

Solve for y in terms of x. 2/3y - 4 = x y = x + 6 y = -x + 4 y = -x + 6 y = x + 4
Aliyah has $24 to spend on seven pencils. After buying them she had $10. How much did each pencil cost?
Ten gallons of paint were poured into two containers of different sizes. Use one variable to express the amount poured into each container
Use the normal model ​n(11371137​,9696​) for the weights of steers. ​a) what weight represents the 3737thth ​percentile? ​b) what weight represents the 9999thth ​percentile? ​c) what's the iqr of the weights
Evaluate a + b when a = –16.2 and b = –11.4 A. –27.6 B. –4.8 C. 4.8 D. 27.6
Link Copied!