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Find the HCF of: 6(p² +p-2), 15(p³ + 8) and 18(4p²-p-18)​
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Find the HCF of: 6(p² +p-2), 15(p³ + 8) and 18(4p²-p-18)​

User Peter Quan
by
8.3k points

1 Answer

7 votes

Answer:

Hello,


answer=\boxed{HCF=3*(p+2)}

Explanation:


6(p^2+p-2)=6(p+2)(p-1)\\\\15(p^3+8)=15(p+2)(p^2-2p+4)\\\\18(4p^2-p-18)=18(p+2)(4p-9)\\\\\boxed{HCF=3*(p+2)}

User Jianru Shi
by
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