Question

Jemuel and Lemuel are asked to paint a house.Jemuel can paint the house by himself 16hrs and Lemuel can paint by himself in 12hrs .How long would it take to paint the house if they work together?​

Answer 1

9 and 3/5 hours or 9 hours and 36 minutes

Explanation:

Rate x times = number of jobs

Jemuel's rate is 1 job/ 16 hours.

Lemuels's rate is 1 job/12 hours.

1/16T + 1/14T = 1 Get a common denominator of 48

3/48T + 2/48 t = 1

5/48T = 1 Multiply both sides by 48/5

(45/5)(5/48)T = 1(48/5)

t = 48/5 = 9 3/5 hours.