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. Verify the concepts you havelearned about the Law of Acceleration in doing some problem – solving exercises.1.The rising concern among athletic trainers regarding concussions among football playershas prompted numerous studies of the effectiveness of protective head gears.

1.One study suggests that concussions may result from impacts rated at 740 m/s2. If a player’s head mass (with helmet) is 6 kg and considered to be a free body, then what net force would be required to produce an acceleration of 740 m/s2?2.Captain John Stapp of the U.S. Air Force tested the human limits of acceleration by riding on a rocket sled of his own design.

2.His rocket sled, known as the Gee Whiz, had a mass of about 82 kg. What net force would be required to accelerate Gee Whiz and 82 kg Stapp at 450 m/s2 (the highest acceleration tested by Stapp)?3.Space Shuttle Max is one of the extreme rides in Enchanted Kingdom.

3.The first of its kindin the country, the roller coaster ride inverts its riders six times. If during one of its operations, a 53 kg boy experiences a net force of 1800 N at the bottom of its roller coaster loop, how fast would he be accelerating at this location ​​

2 Answers

1 vote

Answer: 1. f = 444N

2. f = 36900N

3. a=34 m/s2

Explanation:

f=net force. a=acceleration. m=mass.

f = m*a

1. f = m*a

f = 6 * 740

f = 444N

2. f = 82 * 450

f = 36900N

3. f = m*a

1800=53*a

a=1800/53

a=34 m/s2

User Askaale
by
3.0k points
6 votes

Answer:

1) 4440 N

2) 36900 N

3) 34.0 m/s² (nearest tenth)

Explanation:

Newton's Second Law of Motion

The overall resultant force acting on a body is equal to the mass of the body multiplied by the body's acceleration.


\large\boxed{F_(net)=ma}

  • F = force measured in N (Newtons).
  • m = mass measured in kg (kilograms).
  • a = acceleration measured in m/s² (meters per second squared).

Question 1

Given:

  • m = 6 kg
  • a = 740 m/s²

Substitute the given values into the formula:


\begin{aligned}F_(net) & =ma\\\implies F_(net) & =6 \cdot 740\\& =4440\:\sf N\end{aligned}

Question 2

Given:

  • m = 82 kg
  • a = 450 m/s²

Substitute the given values into the formula:


\begin{aligned}F_(net) & =ma\\\implies F_(net) & =82 \cdot 450\\& =36900\:\sf N\end{aligned}

Question 3

Given:

  • m = 53 kg
  • F = 1800 N

Substitute the given values into the formula:


\begin{aligned}F_(net) & =ma\\\implies 1800& =53a\\a & = (1800)/(53)\\ a& =33.96226415...\\ & = 34.0\:\sf m/s^2 \:\:(nearest\:tenth)\end{aligned}

User Daniel Mizerski
by
3.8k points