Final answer:
According to the Law of Conservation of Mass, the total mass of the reactants must be equal to the total mass of the products in a chemical reaction. In this case, 2 grams of potassium reacts with 5 grams of oxygen. From the balanced equation, 4 moles of potassium react with 1 mole of oxygen to produce 2 moles of potassium oxide. Therefore, the mass of potassium oxide produced is 44.08 grams.
Step-by-step explanation:
According to the Law of Conservation of Mass, the total mass of the reactants must be equal to the total mass of the products in a chemical reaction.
In this case, 2 grams of potassium reacts with 5 grams of oxygen. To find the mass of potassium oxide produced, we need to balance the equation:
4K (s) + O₂(g) → 2K₂O(s)
From the balanced equation, we can see that 4 moles of potassium react with 1 mole of oxygen to produce 2 moles of potassium oxide. Therefore, the molar mass of potassium oxide is calculated as (2 moles of potassium x 39.10 g/mol) + (1 mole of oxygen x 32.00 g/mol) = 110.20 g/mol.
Now, we can determine the mass of potassium oxide produced by setting up a proportion:
(2 grams of potassium oxide) / (110.20 g/mol) = (x grams of potassium oxide) / (5 grams of oxygen)
Solving for x gives us x = 2*110.20/5 = 44.08 grams of potassium oxide.