Question

The length of a rectangle parking area is three times the width.The perimeter is 280 yd.Find the length and width of the parking are.

Answer 1

length = 105 yd

width = 35 yd

Explanation:

Let L = length and W = width.

L = 3W

perimeter = 2(L + W)

280 =2(L + W)

L = 3W

We have a system of 2 equations. Let's use the substitution method to solve it. Substitute 3W for L in the first equation.

280 = 2(3W + W)

140 = 4W

W = 35

L = 3W = 3(35) = 105

length = 105 yd

width = 35 yd