Question

A recent survey by the American Automobile Association showed that a family of two adults and two children on vacation in the United States will pay an average of $247 per day for food and lodging with a standard deviation of $60 per day. You can compute the mean food and lodging cost of a 10-day vacation by multiplying the per-day mean by 10. The standard deviation for the 10-day vacation can be found by multiplying by 10 also.

Note: Please make sure to properly format your answers. All dollar figures in the answers need to include the dollar sign and any amount over 1,000 should include the comma ($2,354.67). All percentage values in the answers need to include a percentage sign (%). For all items without specific rounding instructions, round your answers to two decimal places, show both decimal places (5.06).

a. What is the mean for food and lodging for a 10-day vacation? _______

b. What is the standard deviation of the distribution for the 10-day vacation? ______

c. What is the variance of the distribution for the 10-day vacation? ______

Answer 1

The mean for food and lodging for a 10-day vacation is $2,470. The standard deviation of the distribution for the 10-day vacation is $600. The variance of the distribution for the 10-day vacation is $360,000.

Step-by-step explanation:

a. What is the mean for food and lodging for a 10-day vacation?

To find the mean for food and lodging for a 10-day vacation, we can multiply the per-day mean by 10. The per-day mean is $247. So, the mean for a 10-day vacation is $247 * 10 = $2,470.

b. What is the standard deviation of the distribution for the 10-day vacation?

To find the standard deviation for the 10-day vacation, we can multiply the per-day standard deviation by 10 as well. The per-day standard deviation is $60. So, the standard deviation for the 10-day vacation is $60 * 10 = $600.

c. What is the variance of the distribution for the 10-day vacation?

The variance of a distribution is the square of the standard deviation. So, to find the variance for the 10-day vacation, we can square the standard deviation of $600. The variance is $600^2 = $360,000.