Question

Which sport car motion does Not get any kind of "acceleration?" When a car

A- turns a corner
B- brakes to a stop
C- starts from a traffic stop
D- moves with constant velocity

Answer 1

D- moves with constant velocity

Step-by-step explanation:

As we know that acceleration is tge rate of change in velocity.

Since velocity is constant, the change in velocity is zero (∆v=0)

`{ \tt{acceleration = ( \triangle v)/(t) }} \\ \\ { \tt{acceleration = (0)/(t) }} \\ \\ { \tt{acceleration = 0}}`