Please solve this...... \frac{ {c}^(2) + 2cd - {15d}^(2) }{ {4c}^(2) + 20cd }

Danielmhanover asked Jul 8, 2022

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8 votes

Please solve this......

$\frac{ {c}^(2) + 2cd - {15d}^(2) }{ {4c}^(2) + 20cd }$

Danielmhanover asked Jul 8, 2022

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10 votes

Answer:

$\frac{ {c}^(2) + 2cd - 15 {d}^(2) }{4 {c}^(2) + 20cd} = ((c - 3d)(c + 5d))/(4c(c + 5d) ) \\ \\ \\ = (c - 3d)/(4c)$

I hope I helped you^_^

Dhvanil answered Jul 15, 2022

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