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41 votes
41 votes
What is the pOH of a solution with [OH'] = 9,0 x 10-7?

O A. 7.95
O B. -7.00
C. 9.54
D. 6.04
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Help pls

User Omar Elabd
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1 Answer

11 votes
11 votes

Answer: D (6.04) is the best answer

Step-by-step explanation:

pOH = - log [OH⁻]

pOH = - log (9.0 x 10⁻⁷)

pOH = 6.0457

User GBrian
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