Question

Solve for X
3(x + 7) < 7(x + 2)

Answer 1

`\\ \tt\hookrightarrow 3(x+7)<7(x+2)`

`\\ \tt\hookrightarrow 3x+21<7x+14`

`\\ \tt\hookrightarrow 3x-7x<14-21`

`\\ \tt\hookrightarrow -4x<-7`

`\\ \tt\hookrightarrow 4x>7`

`\\ \tt\hookrightarrow x>7/4`

`\\ \tt\hookrightarrow x\in((7)/(4),\infty)`

Answer 2

x > 7/4

Explanation:

3(x + 7) < 7(x + 2)

Expand brackets: 3x + 21 < 7x + 14

Subtract 14 from both sides: 3x +7 < 7x

Subtract 3x from both sides: 7 < 4x

Divide both sides by 4: 7/4 < x

Therefore x > 7/4