Answer:
The function is exponential
Its equation is
![y = (7)/(3) \cdot((1)/(3) )^x](https://img.qammunity.org/2023/formulas/mathematics/college/rqfcbudienjj3t5irv4mwqqnre9svgb4lj.png)
Explanation:
We can see that, as x increases by a constant y increases by a factor of
![(1)/(3)](https://img.qammunity.org/2023/formulas/mathematics/high-school/rshimc01547v0bylxspiig5y5rp1hyhlbx.png)
So the table represents an exponential equation
The form of the equation is
All we have to do is determine a
Take the entry for x = 0
At x = 0, the equation becomes y =
![a\cdot((1)/(3)) ^ 0](https://img.qammunity.org/2023/formulas/mathematics/college/aoi0n7shdmwq3rzauwgdwmuhd0bel1usf3.png)
Any number raised to the power 0 is 1
So at
![x = 0, y = a\cdot1 = a](https://img.qammunity.org/2023/formulas/mathematics/college/5eutyzxmlzqlnxmowqlomxsehjaqtfpes3.png)
But we know the y value at x = 0 is
So
![a = (7)/(3)](https://img.qammunity.org/2023/formulas/mathematics/college/d0026lqzxnlf79qauvmcxlch1du9rjn6nt.png)
The equation of the function is
We can verify by plugging in a few values for x into the above equation and seeing if the corresponding calculated values concur with the one in the table
For
![x = - 1, y = (7)/(3)\cdot ((1)/(3))^(-1) = (7)/(3)\cdot 3 = 7](https://img.qammunity.org/2023/formulas/mathematics/college/l0x4fnexf6bo1e1lk2b7dzgr7hg0sm417j.png)
You can try the other x values and see that computed and given y values concur