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Solve by Elimination Algebra 2 A park charges $10 for adults and $5 for kids. How many adult tickets and kid tickets were sold, if a total of 524 tickets were sold for a total of $3860 There were _ adults and _ kids tickets sold​

1 Answer

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Answer:

There were 248 adult tickets and 248 kid tickets.

Explanation:

a = number of adult tickets

k = number of kid tickets

a + k = 524 10a + 5k = 3860

Multiply the equation on the right all the way through by -5 so that we can eliminate the k's when we add the equations together.

-5(a+ K) = 524(-5)

-5a - 5k = -2620

Add the two equations together:

-5a - 5k = -2620

10a + 5K = 3860

5a = 1240 Divide both sides by 5

a = 248 There are 248 adult tickets. Plug in 248 for a in either of the original equations.

a + k = 524

248 + k = 524 Subtract 248 from 524 to find the number of kid tickets.

There are 276 kid tickets.

Check:

Plug in 276 for k and 248 for adult to both equations to see if they work

a + k = 524

248 + 276 = 524

524 = 524

10a + 5k = 3860

10(248) + 5(276) = 3860

2480 + 1380 = 3860

38060 = 3860

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