Answer:
A
Explanation:
Given the equations
x = 2y → (1)
3x - 4y = 8 → (2)
Substitute x = 2y into (2)
3(2y) - 4y = 8
6y - 4y = 8
2y = 8 ( divide both sides by 2 )
y = 4
Substitute y = 4 into (1) for corresponding value of x
x = 2(4) = 8
The lines intersect at (8, 4 ) → A