Answer:
25 and 7
Explanation:
You want to find two numbers with a sum of 32 such that the larger is 3 less than 4 times the smaller.
Setup
Let s represent the smaller number. Then the larger is (4s-3) and their sum is ...
s +(4s -3) = 32
Solution
Collect terms to get ...
5s -3 = 32
5s = 35 . . . . . . . add 3
s = 7 . . . . . . . divide by 5
4s-3 = 28-3 = 25 . . . . the larger number
The two numbers are 7 and 25.