374,701 views
7 votes
7 votes
How many

solutions for x does the following equation have?
4/5(20x + 5) = 16x - 2


A. 1
B. -2
C. 0
D. infinite

How many solutions for x does the following equation have? 4/5(20x + 5) = 16x - 2 A-example-1
User Nolonar
by
2.9k points

2 Answers

14 votes
14 votes
the answer will be c zero
User SeyedPooya Soofbaf
by
2.9k points
19 votes
19 votes

Answer:

There are no solutions

Explanation:

4/5 ( 20x + 5 ) = 16x - 2

Distibute on the left:

( 4/5 x 20 x ) + ( 4/5 x 5 ) = 16x - 2

16x + 4 = 16x - 2

Subtract 16x from both sides:

4=-2

Add 2 to each side:

6=0

No solutions

User Olly Hodgson
by
2.4k points