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(4x-1)(3x^2+3x-5) (4x−1)(3x 2 +3x−5)
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(4x-1)(3x^2+3x-5) (4x−1)(3x 2 +3x−5)

User Roboli
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1 Answer

5 votes

Hi.

Answer:


\left(4x-1\right)^2\left(3x^2+3x-5\right)^2

Explanation:


(aa=a^2) \left(4x-1\right)\left(4x-1\right)=\left(4x-1\right)^2\\=\left(4x-1\right)^2\left(3x^2+3x-5\right)\left(3x^2+3x-5\right)\\\left(3x^2+3x-5\right)\left(3x^2+3x-5\right)=\left(3x^2+3x-5\right)^2\\=\left(4x-1\right)^2\left(3x^2+3x-5\right)^2

User Pat Mustard
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