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The distance between John's house and Albert’s house is 8 1/3 miles. A park is located on a straight path between the two houses. If the park is 3 4/5 miles from John’s house, how far is the park from Albert’s house? As a fraction.

User Svyatoslav Danyliv
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2 Answers

26 votes
26 votes

Final answer:

To determine the distance from the park to Albert's house, subtract 3 4/5 miles from 8 1/3 miles, resulting in 3 1/3 miles or 10/3 miles.

Step-by-step explanation:

The question asks to find out how far the park is from Albert's house if the distance between John's house and Albert's house is 8 1/3 miles and the park is 3 4/5 miles from John's house. To solve this, we subtract the distance from John's house to the park from the total distance between John's and Albert's houses.

Firstly, we need to convert the mixed numbers into improper fractions:

8 1/3 miles = (8 × 3 + 1)/3 = 25/3 miles,

3 4/5 miles = (3 × 5 + 4)/5 = 19/5 miles.

Now we subtract the distance from John's house to the park from the total distance:

25/3 miles - 19/5 miles = (83 × 5 - 25 × 3)/15 = (125 - 75)/15 = 50/15 miles,
which simplifies to 10/3 miles or 3 1/3 miles.

Therefore, the park is 3 1/3 miles or 10/3 miles from Albert's house.

User Tom Slabbaert
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2.8k points
18 votes
18 votes

Answer:

The average mass of a group of children is 50 kilograms. Todd, who has a mass of 62 kilograms, then joins the group. This raises the average mass of the group to 52 kilograms. How many children were in the original group

Step-by-step explanation:

User Maharjun M
by
2.7k points
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