Question

I am just clueless!!!!!

Answer 1

6 units

Explanation:

use the distance formula to find the new length of JK, which is J'K'

d =
`√((y-y)^2+(x-x)^2)`

coordinates of J: (-7,3)

coordinates of J': (-7/2, 3/2)

coordinates of K: (3/2, -3/2)

d =
`√((-3/2-3/2)^2+(3/2-(-3/2)^2)`

d =
`√((-6/2)^2+(-10/2)^2)`

d =
`√(3^2+5^2)`

d =
`√(36)`

d = 6