Arithmetic sequence a1=8 d=9

asked Sep 4, 2023 191k views

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6 votes

Answer:

$\ \ \ \ \ \ a_n=8+9(n-1)\\\implies a_n=8+9n-9\\\implies a_n=9n-1$

Explanation:

arithmetic sequence equation:

a_n=a+(n-1)d

where a is the first term and d is the common difference

Therefore,

$\ \ \ \ \ \ a_n=8+9(n-1)\\\implies a_n=8+9n-9\\\implies a_n=9n-1$

Daylight answered Sep 8, 2023

7.8k points

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