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X^3=-115 pleasess i need the answer now

User Mark Pazon
by
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1 Answer

4 votes

Answer:

x = -∛115

Explanation:

x^3 - (-115) = 0

= x^3 + 115

Factoring

(a+b) • (a^2-ab+b^2) =

a^3-a^2b+ab^2+ba^2-b^2a+b^3 =

a^3+(a^2b-ba^2)+(ab^2-b^2a)+b^3=

a^3+0+0+b^3=

a^3+b^3

(115 isn't a cube.)

Polynomial roots

P: -1, -5, -23, -115, 1, 5, 23, 115

Q: 1

P/Q: -1, -5, -23, -115, 1, 5, 23, 115

Divisor(s): None

In these sets of data, there are no rational roots shown.

Step-by-step explanation(part 2):

x^3 + 115 = 0

x^3 = -115

x = ∛-115

Negative numbers will always have real cube roots.

∛ -115 = ∛ -1 × 115 = ∛ -1 × ∛ 115 = (-1) × ∛ 115

Therefore,

x = -∛115

User Gkrdvl
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