HURRY I NEED HELP !!! A line passes through (-1,7) and (2, 10). What is the equation of the line? 3x - y = -16 x - y = -8 x - y = -12 Зх

My account
Edit my Profile
Private messages
My favorites

Ask a Question
Questions
Tags
Categories
Ask a Question

HURRY I NEED HELP !!! A line passes through (-1,7) and (2, 10). What is the equation of the line? 3x - y = -16 x - y = -8 x - y = -12 Зх — у = -4

Rea Haas asked Jul 4, 2022

320,650 views

26 votes

HURRY I NEED HELP

!!!
A line passes through (-1,7) and (2, 10). What is the equation of the line?
3x - y = -16
x - y = -8
x - y = -12
Зх — у = -4

Mathematics
high-school

Rea Haas asked Jul 4, 2022

by Rea Haas

2.6k points

0 Comments

Your comment on this question:

Email me at this address if a comment is added after mine:Email me if a comment is added after mine

Privacy: Your email address will only be used for sending these notifications.

Your answer

Email me at this address if my answer is selected or commented on:Email me if my answer is selected or commented on

Privacy: Your email address will only be used for sending these notifications.

2 Answers

19 votes

Answer: the man who answered first is right its -x+y=8

Explanation:

i took de test

Duroth answered Jul 5, 2022

by Duroth

3.4k points

0 Comments

Your comment on this answer:

Email me at this address if a comment is added after mine:Email me if a comment is added after mine

Privacy: Your email address will only be used for sending these notifications.

14 votes

Answer:

It is x - y = -8

Tom Dudfield answered Jul 8, 2022

by Tom Dudfield

2.8k points

0 Comments

Your comment on this answer:

Email me at this address if a comment is added after mine:Email me if a comment is added after mine

Privacy: Your email address will only be used for sending these notifications.

Ask a Question

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

1.6m questions

2.0m answers

0 Comments

Your comment on this question:

Your answer

2 Answers

0 Comments

Your comment on this answer:

0 Comments

Your comment on this answer:

Other Questions