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4 votes
What is d if
(3d-2)/(8) = -d+16(1)/(4)

1 Answer

5 votes

Answer: d=12

Explanation:


\displaystyle\\(3d-2)/(8) =-d+16(1)/(4) \\\\(3d-2)/(8) =-d+(16*4+1)/(4) \\\\(3d-2)/(8) =-d+(64+1)/(4) \\\\(3d-2)/(8) =-d+(65)/(4)

Multiply both parts of the equation by 8:


\displaystyle\\3d-2=(-d+(65)/(4) )(8)\\\\3d-2=-8d+65*2\\\\3d-2=-8d+130\\\\3d-2+2=-8d+130+2\\\\3d=-8d+132\\\\3d+8d=-8d+132+8d\\\\11d=132\\

Divide both parts of the equation by 11:


d=12

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