Question:- Mike is twice as old as his sister. Together, their ages add up to 30. How old are Mike and his sister?
Given :-
- Mike age is 2 time his sister age
- Mike age + his sister age = 30
Answer:-
Let Mike's sister age be x
Then Mike age ATQ = 2 × age of his sister = 2x
Now According to the Question (ATQ):-
![Mike \: age + his \: sister \: age = 30 \\ 2x + x = 30 \\ 3x = 30 \\ \cancel{3}x = \cancel{30} ^( \: \: 10) \\ x = 10](https://img.qammunity.org/2023/formulas/mathematics/college/sj79eehpet8sgplxslrghyg0trbcsu02oo.png)
So Mike age = 2x = 2×10 = 20
Mike's sister age = x = 10
verification of the answer:-
Just put the value in the equation ATQ :-
![Mike \: age + his \: sister \: age = 30 \\ 20 + 10 = 30 \\ 30 = 30 \\ LHS = RHS](https://img.qammunity.org/2023/formulas/mathematics/college/xprw8287o8gotke6fxn038aqyt1iizx1gv.png)