Question

The length of a rectangle is 1 in. less than 3 times the width. If the perimeter of the rectangle is 46 in., find the length and the width.

Answer 1

`\Large {\mathbb {SOLUTION: }}`

`\: \: \text{L = 3w - 1}`

`\: \: \text{P=46}`

`\: \: \text{2(3w-1) + 2w = 46}`

`\: \: \text{6w - 2 + 2w = 46}`

`\: \: \text{8w = 48}`

`\: \: \text {W = 6 }`

`\: \: \text{L = 17}`

`\: \: \text{Applying the inequalities:}`

`\: \: \text{L>=17 and w=6}`

`\: \: \text{The perimeter is at least 46.}`