Answer:
There are no values of x that make this equation true.
Explanation:
We know h(x)=
![√(x-3) +5](https://img.qammunity.org/2023/formulas/mathematics/high-school/69axvrtev2o92elsdnpdgzhjagq4plquwe.png)
So lets substitute h(x) for 3
3=
![√(x-3)+5](https://img.qammunity.org/2023/formulas/mathematics/high-school/fsvji0bd2k2hnzlgip9bzu4y30yz6esef7.png)
We are going to then subtract 5 from each side leaving us with
-2=
![√(x-3)](https://img.qammunity.org/2023/formulas/mathematics/college/p4eqkpnw43zjz4iwowphajotfxy7bychi2.png)
We then need to get rid of the square root, so we will square both sides. which gives us
4=x-3
We then need to subtract 3 from both sides which leaves us with
x=1
However, when you substitute 1 for x into the original equation, you get
h(x)=
![√(-2)+5](https://img.qammunity.org/2023/formulas/mathematics/high-school/jdm64bz71u0qmi6s9usjs19vi27fwwfscq.png)
Which is not equal to 3
Therefore, there are no values of x that make this equation true.