Question

The length of a rectangle is 4yd longer than its width.

If the perimeter of the rectangle is 68yd, find its length and width.

Answer 1

Pentagon Question

The sides add to 63, so:

`11+3x+11+x+2+2x+3=63 \\ \\ 6x+27=63 \\ \\ 6x=36 \\ \\ x=6 \\ \\ \implies AB=2(6)+3=15`

Rectangle Question

If the width is w, then the length is w+4.

This means that 2(w+w+4)=68.

`2(2w+4)=68 \\ \\ 2w+4=34 \\ \\ 2w=30 \\ \\ w=15`

So, the length is 19 and the width is 15.