Question

How much of a(n) 70% orange juice drink must be mixed with 18 gallons of a 30% orange juice drink to obtain a mixture

that is 50% orange juice?

Answer 1

18 gallons

Explanation:

Start with x gallons of 70% juice and 18 gallons of 30% juice.

Result: x + 18 gallons of 50% juice

0.7x + 0.3 × 18 = (x + 18)(0.5)

0.7x + 5.4 = 0.5x + 9

0.2x = 3.6

x = 18

Answer: 18 gallons