Question

The perimeter of a rectangle is 800 yards. What are the dimensions of the rectangle if the length is 50 yards more than the

width?

Answer 1

225 * 175 yards,

Explanation:

If the width is x then the length is x+50.

Perimeter = 2(width + length)

800 = 2( x + x + 50)

2x + 50 = 400

2x = 350

x = 175

So, the width is 175 yd and length is 225yd.

Answer 2

The length is 225 yd, and the width is 175 yd.

Explanation:

Let w = width.

Then the length = w + 50.

perimeter = 2(length + width)

800 = 2(w + 50 + w)

400 = 2w + 50

2w = 350

w = 175

w + 50 = 225

The length is 225 yd, and the width is 175 yd.