Find the equation of the line which passes through (4,1) and is parallel to the line with equation 2y=x+1

Question

asked Aug 5, 2023 234k views

1 Answer

Juwalter · Answer 1 · 2023-08-12T07:43:26+0000

Parallel to the line:

${\sf{2y = x + 1}}$

${\sf{y = (x)/(2) + (1)/(2 )}}$

Hence Slope:

${\sf{\large{(1)/(2)}}}$

The slope of line of which equation we need is parallel to the line given. Therefore, it's slope also is (m):

${\sf{\large{(1)/(2)}}}$

Also, the line passes through the points (4, 1)

Therefore by the formula of

${\sf{(y - y1) = m(x - x1)}}$

we have:

${\sf{(y - 1) = (1)/(2) (x - 4) }}$

${\sf{2y - 2 = x - 4}}$

${\sf{x - 4 - 2y + 2 = 0}}$

${\sf{\red{\boxed{\sf{x - 2y - 2 = 0}}}}}$