Question

The rhombus shown below has been dissected into smaller rhombuses and

equilateral triangles whose side lengths are all unequal positive integers.
Find the smallest possible perimeter of the rhombus.

Answer 1

Hello,

Answer 176

Explanation:

Very hard as problem.

1. we suppose 2 variables a and b.

we find that b=5a/6

2. One more variable c

we find c=13a/24

3. a must be a multiple of 24 and perimeter is 44*a/6 = 176a/24