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The length of a rectangle is 3ft longer than its width.

If the perimeter of the rectangle is 50ft, find its length and width.

The length of a rectangle is 3ft longer than its width. If the perimeter of the rectangle-example-1

2 Answers

2 votes

Answer: the width is 6.25 ft

And the Length is 18.75 ft

Explanation:

Length = 3w

Width = w

Perimeter = 3w + 3w + w + w

50 = 3w + 3w + w + w

50 = 8w

w = 6.25

Length = 3w

Length = 3(6.25)

Length = 18.75


Therefore the width is 6.25 ft

And the Length is 18.75 ft

User Spidyx
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4 votes

The width of the rectangle is 11 feet, and the length is 14 feet.

Let's denote the width of the rectangle as w and the length as l. According to the given information, the length is 3 feet longer than the width. So, we can express the length in terms of the width:

l=w+3

The formula for the perimeter (P) of a rectangle is given by:

P=2(l+w)

In this case, the perimeter is given as 50 feet, so we can set up the equation:

50=2(w+(w+3))

Now, solve for w:

50=2(2w+3)

Distribute the 2:

50=4w+6

Subtract 6 from both sides:

44=4w

Divide by 4:

w=11

Now that we have the width (w), we can find the length (l) using the relationship

l=w+3:

l=11+3=14

So, the width of the rectangle is 11 feet, and the length is 14 feet.

User Melculetz
by
7.8k points
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