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Suppose that a>1/2 and the parabola with equation y=ax^2+2 has vertex V. The parabola intersects the line with equation y=-x+4a at points B and C, as shown. If the area of triangle VBC is 72/5, determine
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Suppose that a>1/2 and the parabola with equation y=ax^2+2 has vertex V. The parabola intersects the line with equation y=-x+4a at points B and C, as shown. If the area of triangle VBC is 72/5, determine the value of A.

Suppose that a>1/2 and the parabola with equation y=ax^2+2 has vertex V. The parabola-example-1
User ZeroOneZeroR
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Answer:

Y = ×+ 4 a 75 VBC

I HOPE ITS HELP

User Iamsar
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