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Given f(x) = 2x - 1, g(x) = 3x^2 + 5, and h(x) = 4x+ 6 find h(g(f(x))).

User Beothorn
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1 Answer

1 vote

Answer:

48x^2 - 48x + 38

Explanation:

To get the composite function first understand the process of which a function inside another operates.

First solve one step at a time by trying to evaluate the inside before evaluating the outside using substitution.

For instance, h(g(f(x))) is the h function of g function of f.

Since f(x) is the inner component of the composite function, replace the x of g with the value of f(x).

Such that g(x) = 3x^2 + 5 → 3(f(x))^2 + 5 →

3(2x - 1)^2 + 5 → 3(2x - 1)(2x - 1) + 5 [foil] → 3(4x^2 - 4x + 1) + 5 → 12x^2 - 12x + 3 + 5 →

12x^2 - 12x + 8

Thus g(f(x)) = 3(f(x))^2 + 5 = 12x^2 - 12x + 8.

Finally to compute h(g(f(x))), using the process from the first composite function, same can be applied here:

Since h(x) = 4x + 6 →

h(g(f(x))) =

h(12x^2 - 12x + 8) =

4(12x^2 - 12x + 8) + 6 [distribute] →

48x^2 - 48x + 32 + 6 [combine like terms] →

48x^2 - 48x + 38

User Alex Broadwin
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