Question

Help me pleasee
Questions r in picture

Answer 1

`\large \bf\implies(12)/(61)`

Explanation:

Given :

`\tt (8)/(101) , (9)/(91) , (10)/(81) , (11)/(71) ...`

To Find :

• nth term

Solution :

We have to add 1 in numerator and -10 in denominator because

`\tt (8)/(101) , (9)/(91) , (10)/(81) , (11)/(71) ...[Given]`

`(8 \: + \: 1)/(101 \: - \: 10) = (9)/(91) \\\\ (9 + 1)/(91 - 10) = (10)/(81) \\ \\ (10 + 1)/(81 - 10) = (11)/(71) \\ \\ (11 + 1)/(71 - 10) = (12)/(61) ...`

The difference is 1 in numerator so we add 1 and the difference is -10 in denominator so we subtract -10.