Question

A student threw a ball horizontally out of a window 5.9 meters above the ground. It

was caught by another student who was 14.6 meters away. What was the horizontal
velocity of the ball?

Answer 1

Step-by-step explanation:

In the absence of air resistance, the horizontal velocity will not change.

Assuming the ball was caught at ground level,

The time of flight is

t = √(2s/a) = √(2(5.9) / 9.8) = 1.1 s

the horizontal velocity is

vx = 14.6/1.1 = 13.3 m/s