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If the applied force (F) is 14 N and the frictional force (f) is 3 N, what would the acceleration be on this 3.5 kg box?
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If the applied force (F) is 14 N and the frictional force (f) is 3 N, what would the acceleration be on this 3.5 kg box?

User Andrepnh
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1 Answer

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Answer:a = F/m so

11/3.5 times= 3.14 m/s

Step-by-step explanation:

User Weia Design
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