Question

A 40.0-kg child swings in a swing supported by two chains, each 3.00m long. The tension in each chain at the lowest point is 350N . Find (b) the force exerted by the seat on the child at the lowest point. (Ignore the mass of the seat.)

Answer 1

The force exerted by the seat on the child at the lowest point is 1080 N.

Step-by-step explanation:

To find the force exerted by the seat on the child at the lowest point, we can use Newton's second law. The force exerted by the seat is equal to the child's mass times the acceleration. Since the child is swinging in a vertical circular motion, the acceleration is given by v^2/r, where v is the child's speed at the lowest point and r is the length of the swing chains. In this case, the child's mass is 40.0 kg, the speed is 9.00 m/s, and the length of the swing chains is 3.00 m.

Using the formula for acceleration, we can calculate: a = (9.00 m/s)^2 / 3.00 m = 27.0 m/s^2.

Finally, we can calculate the force exerted by the seat: F = m * a = 40.0 kg * 27.0 m/s^2 = 1080 N.