Question

Help!! ASAP!!! 1. Solve:

6(6-4x) + 16x = 8x + 4

2. Evaluate the following expression
|-3d-6| + |-5-d^2| for d=3

3. Solve the formula for t.
S=5r^2t

5. Which equation’s line is steeper and explain how you know
y=3x+7 or
y=1/2x+9

Answer 1

#1

`{ \tt{6(6 - 4x) + 16x = 8x + 4}} \\ { \tt{12 - 36x + 16x = 8x + 4}} \\ { \tt{12 - 20x = 8x + 4}} \\ { \tt{ - 20x - 8x = 4 - 12}} \\{ \tt{ - 28x = - 8}} \\ { \boxed{ \tt{ \: x = - (2)/(7) }}}`

#2

`= { \tt{ | - 3d - 6| + | - 5 - {d}^(2) | }} \: \: (d = 3) \\ = { \tt{ |( - 3 * 3) - 6| + | - 5 - {3}^(2) | }} \\ = { \tt - 15} \\ = { \tt{15 + 14}} \\ { \tt{ = 29}}`

#3

`{ \tt{s = 5 {r}^(2)t }} \\ \\ { \boxed{ \tt{t = \frac{s}{5 {r}^(2) } }}}`

#5

`{ \tt{for \: \: { \red{y = 3x + 7}}} \:} \\ \dashrightarrow \: { \rm{gradient = 3}} \\ \\ { \tt{for \: \: { \blue{y = (1)/(2)x + 9}} }} \\ \dashrightarrow \: { \rm{gradient = (1)/(2) }}`

Therefore, y = 3x + 7 is steeper.

Step-by-step explanation: An equation with smaller ∆x (difference in x-coordinates) is steeper than one with great ∆x respective of ∆y