Question

Can any one help please :)

Answer 1

B

Explanation:

First, subtract 3 by the numbers

-8 > 4x > 4

Remember to flip the inequality signs

Second, divide all the numbers by 4

-2 < x < 1

Flip the inequality signs again

-2 > x > 1

I am not very experienced with these problems so I might be wrong.

Answer 2

B: x > -2 and x ≤ 1

Explanation:

–5 < 4x + 3 ≤ 7

Since -5 is less than 4x + 3, and 4x + 3 is greater than or equal to 7:

We can solve the given inequality as –5 < 4x + 3 and 4x + 3 ≤ 7 to find the possible intervals for x:

Let's start with –5 < 4x + 3 by switching or rewriting the inequality statement as:

4x + 3 > –5

Then, we can subtract 3 from both sides of the inequality to isolate 4x:

4x + 3 – 3 > –5 – 3

4x > – 8

Divide both sides of the inequality by 4:

`(4x)/(4) > (-8)/(4)`

x > –2

Next, we can work on 4x + 3 ≤ 7:

4x + 3 ≤ 7

Subtract 3 from both sides of the inequality:

4x + 3 – 3 ≤ 7 – 3

4x ≤ 4

Divide both sides of the inequality by 4 to solve for x:

`(4x)/(4) \leq (4)/(4)`

x ≤ 1

So, the answer is OPTION B: x > -2 and x ≤ 1