Final answer:
To stop the 7 kg shopping cart in 2 seconds from an initial velocity of 3.5 m/s, an average net force of -12.25 N is required. To stop the 8500 kg truck in 10 seconds from an initial velocity of 20 m/s, an average net force of -17000 N is required.
Step-by-step explanation:
1. To find the average net force required to stop the shopping cart, we can use the equation:
F = m * a
Where F is the force, m is the mass, and a is the acceleration. In this case, the acceleration is calculated using the formula:
a = (final velocity - initial velocity) / time
Substituting the given values, we have:
a = (0 - 3.5) m/s / 2 s = -1.75 m/s²
Now, we can calculate the force:
F = 7 kg * (-1.75 m/s²) = -12.25 N
Since force is a vector quantity, the negative sign indicates that the force is in the opposite direction of the initial motion.
2. Using the same equation, we can find the average net force required to stop the truck:
F = m * a
First, calculate the acceleration:
a = (0 - 20) m/s / 10 s = -2 m/s²
Substituting the given values:
F = 8500 kg * (-2 m/s²) = -17000 N
Once again, the negative sign indicates that the force is in the opposite direction of the initial motion.