Question

In this figure AB and CD are parallel. M is the mid point of BC. Prove that the area of ∠DCM ∠BMN are equal?​

Answer 1

Answer :-

M is the mid point of BC. So ∠MDC = ∠N and ∠DCM is ∠MBN ∠DMC = ∠BMN

All the sides of the two angles are equal.So the area of ∠DCM = ∠BMN