Question

If x2 + y2 =86 and x y = -16 find the value of (x-y)2

Answer 1

54 is the value of (x-y)^2

Explanation:

Given:

Equation 1:
`x^(2) + y^(2) = 86`

Equation 2: xy = - 16

Multiply Equation 2 with 2 on both sides: 2xy = -32

Find value of(Equation 3) :
`(x-y)^2`

`(x-y)^2 = x^(2) + y^(2) + 2xy`

Put the value of equation 1 and equation 2 in equation 3

i.e.
`(x-y)^2 = (x^(2) + y^(2)) + (2xy)`

`(x-y)^2 = (86) + (-32)`

`(x-y)^2 = 54`

Answer 2

(x-y)^2=118

Explanation: