Question

a square has a perimeter of 8 and one vertex at (2, 2). what could be the location of another vertex of this shape? (a) (1, 5) (b) (-2, 2) (c) (2, 3) (d) (0, 0)a square has a perimeter of 8 and one vertex at (2, 2). what could be the location of another vertex of this shape? (a) (1, 5) (b) (-2, 2) (c) (2, 3) (d) (0, 0)

Answer 1

a perimeter of 8 for a square means that the side lengths would be 8/4, which is 2

So, a square has 4 corners, meaning that there are 3 more vertexes other that (2,2).

2 of those vertexes will be adjacent to the point (2,2), and at a distance of 2 away.

the 3rd vertex will be across from (2,2) diagonally. the diagonal of a square is equal to:
`√(2)a`, where
`a` is the side length. so this vertex will be a distance of
`2√(2)` away

it would be easier to graph this, but anyways.

none of those options are a distance of 2 from (2,2). So we are looking for the point diagonally across from (2,2)

if you graph it, you would clearly see that (0,0) fits perfectly. Otherwise use the distance formula and you should get a distance of
`2√(2)`