Answer:
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Explanation:
Given two sets which are:

To find
(A union B), we will simply merge both sets together - basically add all elements into one set. Therefore:

However, we do not write duplicate elements in set so we will have to take one of duplicates out. We will be able to rewrite the union set above as:

To find
(A minus B), we will only take elements that are apart of set A.
This means that if an element is in set A and not in set B then that element will be apart of A - B.
On the other hand, if an element is in set A but if it's also in set B then it'll be cleared out as A - B states that it'll only take in elements that are apart of set A and being apart of both sets will not count in.
Thus, 2 and 3 are not counted in since they are also apart of set B too although they both are apart of set A.
Therefore:
